解题思路
数组中存在0,结果为0。否则,奇数个负数,结果为-1;偶数个负数结果为1
时间复杂度
O(n)
空间复杂度
O(1)
代码
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| class Solution: def arraySign(self, nums: List[int]) -> int: sign = 1 is_zero = False
for num in nums: if num == 0: is_zero = True break if num < 0: sign *= -1
return not is_zero and sign or 0
|