leetcode 20. 有效的括号

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解题思路

使用 “栈” 模拟即可

代码

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class Solution:
    def isValid(self, s: str) -> bool:
        stack = []
        for char in s:
            if not stack:
                stack.append(char)
                continue

            if stack[-1] == '(' and char == ')':
                stack.pop()
            elif stack[-1] == '{' and char == '}':
                stack.pop()
            elif stack[-1] == '[' and char == ']':
                stack.pop()
            else:
                stack.append(char)

        return not stack